a/b+b/a=1, now proof that, a3+b3=0
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ry5e53e
Step-by-step explanation:
e
Answered by
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Step-by-step explanation:
a/b+b/a=1
a²+b²=ab.
add both side 2ab
a²+b²+2ab = 3ab
(a+b)²= 3ab equation (1)
(a+b) = (3ab)¹/² equation (2)
by equation (1)
(a+b)² =3ab
{(a+b)²}³/² = (3ab)³/²
(a+b)³ = (27a³b³)¹/²
a³+b³+3a²b+3ab² = 3ab(3ab)¹/²
a³+b³ = 3ab(3ab)¹/² -3a²b -3ab²
a³+b³ = 3ab{ (3ab)¹/² - a - b}
a³+b³ =3ab(0) by equation (2)
a³+b³ = 0
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