Math, asked by mondalsayan1423, 2 months ago

a/b+b/a=1, now proof that, a3+b3=0​

Answers

Answered by sw232740
0

Answer:

ry5e53e

Step-by-step explanation:

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Answered by pulkitverma1983
0

Step-by-step explanation:

a/b+b/a=1

a²+b²=ab.

add both side 2ab

a²+b²+2ab = 3ab

(a+b)²= 3ab equation (1)

(a+b) = (3ab)¹/² equation (2)

by equation (1)

(a+b)² =3ab

{(a+b)²}³/² = (3ab)³/²

(a+b)³ = (27a³b³)¹/²

a³+b³+3a²b+3ab² = 3ab(3ab)¹/²

a³+b³ = 3ab(3ab)¹/² -3a²b -3ab²

a³+b³ = 3ab{ (3ab)¹/² - a - b}

a³+b³ =3ab(0) by equation (2)

a³+b³ = 0

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