a÷b+b÷a=1, then find the value of a^3+b^3
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considering the first letter to be a and not A
a/b + b/a = 1
=> a2 + b2 = ab (1)
a3 + b3 = (a+b)(a2 - ab + b2)
= (a+b)(ab - ab) [putting value of (1)]
= 0
a/b + b/a = 1
=> a2 + b2 = ab (1)
a3 + b3 = (a+b)(a2 - ab + b2)
= (a+b)(ab - ab) [putting value of (1)]
= 0
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