Question

a/b +b/a (ab not equal to 0 then a cube -b cube
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Answer 1

Answer:

0

Step-by-step explanation:

$\frac{a}{b} \: + \: \frac{b}{a} \: = \: - 1$

Taking LCM, we get

$\frac{ {a}^{2} \: + \: {b}^{2} }{ab} \: = \: - 1$

${a}^{2} \: + \: {b}^{2} \: = \: - ab$

${a}^{2} \: + \: {b}^{2} \: + \: ab \: = \: 0$

Multiply (a - b) on both sides.

$(a - b)( {a}^{2} \: + \: ab \: + \: {b}^{2} ) \: = \: 0(a - b)$

${a}^{3} \: - \: {b}^{3} \: = \: 0$