Question

a/b+b/c-c/a=a/b find b​

Answer 1

Answer:

Step-by-step explanation:

To add:

a−b+ab, b−c+bc, c−a+ac

a−b+b−c+c−a +ab+bc+ac

=0+ab+bc+ac

=ab+bc+ac

Answer 2

Step-by-step explanation:

a/(b+c)=b/(c+a)=c/(a+b)=ka/(b+c)=b/(c+a)=c/(a+b)=k

a=k(b+c)a=k(b+c)

b=k(c+a)b=k(c+a)

c=k(a+b)c=k(a+b)

by property sum of numerator/sum of denominator is also = k

a+b+c/2(a+b+c)=ka+b+c/2(a+b+c)=k

k=1/2k=1/2

If a+b+c=0a+b+c=0

a+b=−corb+c=−aa+b=−corb+c=−a

a/b+c=a/−a=−1=ka/b+c=a/−a=−1=k

So k=−1or1/2