a^b=b^c=c^a Then find value of abc
Anonymous:
actually this question would be solved by using the concept of logarithm
n it seems that this ques is frm 9 standard
so i waana ask whether the user wud b able 2 grab up2 sch lvl or nt?
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suppose, a^b=b^c=c^a=k, some constant k.
then, taking log on both the sides we get,
loga^b=logk
=>b×loga=logk
=>b=log(k-a). similarly,
c=log(k-b) and a=log(k-c).
then, a×b×c=logk/loga×logk/logb×logk/logc=1.
then, taking log on both the sides we get,
loga^b=logk
=>b×loga=logk
=>b=log(k-a). similarly,
c=log(k-b) and a=log(k-c).
then, a×b×c=logk/loga×logk/logb×logk/logc=1.
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