A/b=b/c prove that (a+b+c) (a2+b2+c2)
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If a,b,c are in continued proportion prove that: ( a+b+c)(a-b+c)=a2 +b2+c2
Asked by munnamgautam20 | 25th Jan, 2019, 10:29: PM
Expert Answer:
if a, b,c are in continued proportion, then a = a, b = ar and c = ar2 , where r is common ratio
LHS = (a+b+c)(a-b+c) = a2(1+r+r2)(1-r+r2) = a2(1+r+r2 -r -r2 -r3 +r2 +r3 +r4 ) = a2(1+r2 +r4 )
RHS = (a2+b2+c2) = a2(1+r2+r4)
It is proved that LHS = RHS, hence (a+b+c)(a-b+c) = (a2+b2+c2)
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