Question

a/b=b/c then prove that a/a+b=a-b/a-c

Answer 1

Answer:

(A + B) * (A’ + C)

→ AA’ + AC + A’B + BC

→ 0 + AC + A’B + BC

→ AC + CB + A’B

By the consensus theorem:

xy + yz + x’z = xy + x’z

Let A = x, B = z, C = y

→ AC + CB + A’B = xy + yz + x’z

→ AC + A’B = xy + x’z

Therefore, (A + B) * (A’ + C) = AC + A’B

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

a.b=a.c

a.b−a.c=0

a.(b−c)=0

∣a∣.∣b−c∣cosθ=0

⇒∣a∣

=0 also cosθ



=0

⇒a.b=a.c



=0

⇒∣b−c∣=0

∴b=c