Question

(a+b)(-b-y)=0
solve this problem
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Answer 1

Answer:

Here is you answer mate

Step-by-step explanation:

AB = [(3, 0),(0, 4)][(a, b),(0, c)] = [(3a + 0, 3b + 0),(0 + 0, 0 = 4c)] = [(3a, 3b),(0, 4c)]`

A+B=[3004]+[ab0c]=[3+ab04+c]

Given AB = A + B

∴[3a3b04c]=[3+ab04+c]

Comparing the correspomding elememts we get

3a = 3 + a

=> 2a = 3

⇒a=32

3b = b => b = 0