Question

a+b+c=0
-a-3b=0
-2a-2c=1
find a b c values
​

Answer 1

Given :

a+b+c=0

-a-3b=0

-2a-2c=1

To Find : Values of a , b & c

Solution:

a+b+c=0    

-a-3b=0    

-2a-2c=1    

-a-3b=0  

=> 3b = - a

=> b = - a/3

-2a-2c=1    

=> 2c  = - 1 - 2a

=> c = -( 1 +  2a)/2

a+b+c=0  

=> a - a/3 - ( 1 +  2a)/2 = 0

=> 6a  - 2a  -  3  - 6a = 0

=>  2a = - 3

=> a = - 3/2

  b = -  (-3/2)/3

=> b = 1/2

c = -( 1 +  2(-3/2))/2  

=> c =  1

a = - 3/2 , b = 1/2  , c = 1

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