a+b+c=0, a²+b²+c²-3abc=?
Answers
Answered by
9
Answer:
a^2+b^2+c^2-ab-bc-ca=0
Multiplying both sides by (a+b+c).
(a+b+c).(a^2+b^2+c^2-ab-bc-ca)= (a+b+c).0
or. a^3+b^3+c^3-3abc=0
or. a^3+b^3+c^3 = 3abc. Proved.
Answered by
0
Answer:
(a+b-c)square
Step-by-step explanation:
square means2....
Similar questions