Question

a+b+c=0, a²+b²+c²-3abc=?​

Answer 1

Answer:

a^2+b^2+c^2-ab-bc-ca=0

Multiplying both sides by (a+b+c).

(a+b+c).(a^2+b^2+c^2-ab-bc-ca)= (a+b+c).0

or. a^3+b^3+c^3-3abc=0

or. a^3+b^3+c^3 = 3abc. Proved.

Answer 2

Answer:

(a+b-c)square

Step-by-step explanation:

square means2....