a+b+c=0 & (a,b,c is not equal to zero) but prove that asuqare/bc+bsuqare/ca+csquare/ab=3
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It’s not required that a=b=c for this identity to hold true.
As we know
a3 +b3 + c3 – 3abc = (a+b+c) (a2 + b2 + c2 – ab – bc – ca)
If a+b+c = 0 , then your given statement is true
Also if a=b=c then either all are positive numbers or all should be negative numbers which cannot sum upto zero.
It’s not required that a=b=c for this identity to hold true.
As we know
a3 +b3 + c3 – 3abc = (a+b+c) (a2 + b2 + c2 – ab – bc – ca)
If a+b+c = 0 , then your given statement is true
Also if a=b=c then either all are positive numbers or all should be negative numbers which cannot sum upto zero.
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