Math, asked by eddggh1020, 11 months ago

A+b+c=0 and 3abc=27 find a^3+b^3+c^3=

Answers

Answered by kasikayal2001

0

Answer:

Step-by-step explanation:

a³+b³+c³ -3abc =(a+b+c)(a²+b²+c²-ab-bc-ac)

since a+b+c = 0

a³+b³+c³ = 3abc

= 27

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