Question

a+b+c=0 proof that a3+b3+c3=3abc​

Answer 1

Answer:

We know,

a3 +b3 +c3 −3abc=(a+b+c)(a2 +b2+c2 −ab−bc−ca)

Putting a+b+c=0 on RHS, we get,

a3 +b3+c3 −3abc=0

⟹a3+b3+c3 =3abc, Hence proved.