Question

a+b+c=0 prove a2/bc+b2/ac+c2/ab=3

Answer 1

hope it would be helpful

Answer 2

Solution:

It is given that,

a+b+c=0 ----(1)

To prove:

a²/bc + b²/ac + c²/ab = 3

Explanation:

______________________

We know that,

if x+y+z = 0 then

x³+y³+z³ =3xyz ------(2)

______________________

LHS = a²/bc + b²/ac + c²/ab

= a³/abc + b³/abc + c³/abc

=( a³+b³+c³)/(abc)

= (3abc)/(abc) [ from (2)]

After cancellation, we get

= 3

Therefore,

If a+b+c=0 then

a²/bc + b²/ac + c²/ab = 3

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