Question

a+b+c=0 prove that a cube+ b cube +c cube =3abc​

Answer 1

Answer:

liloljk durg jail meltdowns

Answer 2

Answer:

a³+b³ + c³ = 3abc.

Step-by-step explanation:

Now, a³+b³+ c³

= (a+ b + c) (a2 + b2 + c2 – ab – be – ca) + 3abc

[using identity, a³+b³ + c³ – 3 abc = (a + b + c)(a2+b2+c2 –ab–bc-ca)]

= 0 + 3abc [∴ a + b + c = 0]

a³+b³+c³= 3abc.

please like the answer.