a+b+c =0 than prove a3+b3+c3=3abc
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this the example of this question
if a=13
b=-8
c=-5
i hope i help u
please mark my ans as brainlient
if a=13
b=-8
c=-5
i hope i help u
please mark my ans as brainlient
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TheImmortal49:
You cannot take the variables to be of any value
variables are variables
they cannot be taken as numbers of any choice unless specified
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Answered by
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a+b+c = 0
therefore, a+b = -c .......EQ(1)
We know that,
a+b = -c
or, (a+b)³ = (-c)³
or, a³ + b³ + 3ab(a + b) = -c³
[using (a+b)³ = a³+b³ + 3ab(a+b)]
or, a³ + b³ + c³ = -3ab(a+b)
or, a³ + b³ + c³ = -3ab(-c)
[putting the value of (a+b) from EQ(1)]
or, a³+b³+c³=3abc
HOPE THIS HELPS!!!!!
therefore, a+b = -c .......EQ(1)
We know that,
a+b = -c
or, (a+b)³ = (-c)³
or, a³ + b³ + 3ab(a + b) = -c³
[using (a+b)³ = a³+b³ + 3ab(a+b)]
or, a³ + b³ + c³ = -3ab(a+b)
or, a³ + b³ + c³ = -3ab(-c)
[putting the value of (a+b) from EQ(1)]
or, a³+b³+c³=3abc
HOPE THIS HELPS!!!!!
PLEASE PLEASE PLEASE PLEASE MARK AS BRAINLIEST
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