a^⅓+b^⅓+c^⅓ = 0. then
DaAnonymous:
then...
options are a) a³+b³+c³= 0, b) a+b+c =3(abc)^⅓, c) a+b+c= 3abc d) a+b+c = 3a^⅓b^⅓c^1
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what will be the ans
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heya...!!!!
if
if (x + y + z = 0),
then, x³ + y³ + z³ = 3xyz ................ (1)
now,
x⅓ + y⅓ + c⅓ = 0
according to--(1)
(x⅓)³ + (y⅓)³ + (z⅓)³ = 3(x⅓×y⅓×z⅓)
=> x + y + z = 3(xyz)⅓
hope it's help you
if
if (x + y + z = 0),
then, x³ + y³ + z³ = 3xyz ................ (1)
now,
x⅓ + y⅓ + c⅓ = 0
according to--(1)
(x⅓)³ + (y⅓)³ + (z⅓)³ = 3(x⅓×y⅓×z⅓)
=> x + y + z = 3(xyz)⅓
hope it's help you
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