a+b+c=0, then 3abc is equal to ?
pravin3103:
correct answer is -3(a+b)(b+c)(a+c)
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a + b + c = 0
a = -(b + c)
b = -(a + c)
c = -(a + b)
Putting values of a,b, and c
3abc = 3 * [-(b + c)] * [-(a + c)] * [-(a + b)]
= -3(a+b)(b+c)(a+c)
a = -(b + c)
b = -(a + c)
c = -(a + b)
Putting values of a,b, and c
3abc = 3 * [-(b + c)] * [-(a + c)] * [-(a + b)]
= -3(a+b)(b+c)(a+c)
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