a+b+c=0 then a^2/bc+b^2/ca+c^2/ab=?
Anshulmalik:
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Answers
Answered by
3
Answer:
Step-by-step explanation:
a2/bc + b2/ca + c2/ab LCMof the denominators bc, ca and ab is abc. =(a3 + b3 + c3) / abc Given that a + b + c = 0 Thus, a3 + b3 + c3 = 3abc Replacing numerator with 3abc, 3abc / abc = 3
Answered by
6
Answer:
3
Explanation:
_____________________
We know that,
if a + b + c = 0 then
a³+b³+c³ = 3abc
_____________________
It is given that,
a+b+c=0 then
a³+b³+c³ = 3abc ----(1)
Now ,
a²/bc + b²/ca + c²/ab
= (a³+b³+c³)/(abc)
= (3abc)/(abc)
= 3
••••
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