Math, asked by Anshulmalik, 1 year ago

a+b+c=0 then a^2/bc+b^2/ca+c^2/ab=?


Anshulmalik: ok
kuttimabubbly22: Those are my nick name
Anshulmalik: plz say me i love you
kuttimabubbly22: What???
kuttimabubbly22: Do u like me seriously
Anshulmalik: yes
kuttimabubbly22: Really???????
Anshulmalik: really
kuttimabubbly22: Ooo lovely
sarthakdude: Hey wts going on

Answers

Answered by abiramiragu
3

Answer:

Step-by-step explanation:

a2/bc + b2/ca + c2/ab LCMof the denominators bc, ca and ab is abc. =(a3 + b3 + c3) / abc Given that a + b + c = 0 Thus, a3 + b3 + c3 = 3abc Replacing numerator with 3abc, 3abc / abc = 3

Answered by mysticd
6

Answer:

3

Explanation:

_____________________

We know that,

if a + b + c = 0 then

a³+b³+c³ = 3abc

_____________________

It is given that,

a+b+c=0 then

a³+b³+c³ = 3abc ----(1)

Now ,

a²/bc + b²/ca + c²/ab

= (a³+b³+c³)/(abc)

= (3abc)/(abc)

= 3

••••

Similar questions