Question

a⅓+b⅓+c⅓=0,then (a+b+c)³=27abc.​

Answer 1

Step-by-step explanation:

Given sin

2

θ=

2

1

1−cos

2

θ=

2

1

⟹cos

2

θ=1−

2

1

⟹cos

2

θ=

2

1