Question

a+b+c=0 then (a+b-c)^3 + (b+c-a)^3 + (c+a-b)^3 + xabc =0 then value of x​

Answer 1

Answer:

-3

Step-by-step explanation:

let us consider

A = a + b - c

B = b + c -a

C = c + a - b

A + B + C = a + b - c + b + c - a + c + a - b = 0

if,

a + b + c = 0

then,

(a+b-c)³ + (b+c-a)³ + (c+a-b)³ = 3abc

on substituting,

3abc + xabc = 0

x must be -3 to get the value as 0 for the above equation

hope it helps u....,

if u have any problem with this,

if,

if,a + b + c = 0

if,a + b + c = 0then,

if,a + b + c = 0then,(a+b-c)³ + (b+c-a)³ + (c+a-b)³ = 3abc

it is a formula ,okay ..... ,

hope u understood