a+b+c=0,then (a2/bc+b2/ca+c2/ab)=?
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3
Answer:
0 (zero)
Step-by-step explanation:
a²/bc+b²/ca+c²/ab
=a³+b³+c³
abc
=(a+b+c)(a²+b²+c²-ab-bc-ca)
abc
since a+b+c=0, the above expression is also 0
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