Question

a+b+c =0 then a3+b3+c3=
0-0
0
O- abc
0 -3abc
Qabc​

Answer 1

Answer:

Step-by-step explanation:

Since, a  

3

+b  

3

+c  

3

−3abc=(a+b+c)(a  

2

+b  

2

+c  

2

−bc−ca−ab)

Given, a+b+c=0

∴a  

3

+b  

3

+c  

3

−3abc=0

∴a  

3

+b  

3

+c  

3

=3abc

Option B is correct.