a+b+c=0 then find a3 +b3 +c3 ?
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4
a3+b3+c3-3abc=(a+b+c)(a2+b2+c2-ab-bc-ac)
a3+b3+c3-3abc=0(a2+b2+c2-ab-bc-ac)
a3+b3+c3-3abc=0
a3+b3+c3=3abc
hope this helps!
a3+b3+c3-3abc=0(a2+b2+c2-ab-bc-ac)
a3+b3+c3-3abc=0
a3+b3+c3=3abc
hope this helps!
mehak105:
thbkuuu
Answered by
9
I hope that it will helps you.
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