Question

a + b + c = 0 then find the value​

Answer 1

Answer:

a3+b3+c3+-3abc=(a+b+c)(a2+b2+c2-ab-ac-bc)if a

Answer 2

Answer:

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Question

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If a+b+c=0, then the value of a

2

(b+c)+b

2

(c+a)+c

2

(a+b) is:

Medium

Solution

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Correct option is C)

As given⇒a+b+c=0

So⇒a+b=−c

⇒b+c=−a

⇒c+a=−b

⇒a

2

(b+c)+b

2

(c+a)+c

2

(a+b)

If we put the value then

⇒a

2

(−a)+b

2

(−b)+c

2

(−c)

⇒−a

3

−b

3

−c

3

⇒−(a

3

+b

3

+c

3

)

∵(a

3

+b

3

+c

3

)=(a+b+c)(a

2

+b

2

+c

2

+3abc)

⇒−(a

3

+b

3

+c

3

)=(0)(0+3abc)

⇒−(a

3

+b

3

+c

3

)=3abc

so

⇒a

2

(b+c)+b

2

(c+a)+c

2

(a+b)=−3abc

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