Math, asked by sahiluday9659, 11 months ago

a+b+c=0 then find the value of (a+b-c) (b+c-a) (c+a-b)

Answers

Answered by spiderman2019
0

Answer:

-8abc

Step-by-step explanation:

a+b+c = 0.

(a+b-c) (b+c-a) (c+a-b) = (-c - c ) (-a -a)(-b -b)

                                      = (-2c) * (-2a) * (-2b)

                                      = - 8abc

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