Question

a+b+c =0 then value of a²+b²+c² ÷bc + ca+ab spam will be reported​

Answer 1

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Given,

a+b+c=0

we know that,

if a+b+c=0, then a³+b³+c³-3abc

Now,

(a²/bc)+(b²/ac)+(c²/ab)=(a³ + b³ + c³)/abc

= 3abc/abc

=3

Answer 2

Answer:

Given,

a+b+c=0

we know that,

if a+b+c=0, then a³+b³+c³-3abc

Now,

(a²/bc)+(b²/ac)+(c²/ab)=(a³ + b³ + c³)/abc

= 3abc/abc = 3.

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