Question

(A+B+C) =0
THEN What is the value of (a+b-c)^3+(a+c-b)^3+(b+c-a)^3
plz ans fast

Answer 1

a+b+c=0

then a+b=-c

a+c=-b

b+c=-a

replace it.

(-c-c)^3+(-b-b)^3+(-a-a)^3= -a^3-b^3-c^3

= - ( a^3+b^3+c^3)

= -3abc

That's your answer. Please mark it brainliest as I have given a complete answer.

Thanks

Answer 2

As a+b=-c,a+c=-b,b+c=-a

Answer is -8(a^3+b^3+c^3)