Question

a+b+c=0, then what is the value of a2+ b2+c2/a2- bc=?

Answer 1

a2/bc + b2/ca + c2/ab  LCMof the denominators bc, ca and ab is abc.  =(a3 + b3 + c3) / abc  Given that a + b + c = 0  Thus, a3 + b3 + c3 = 3abc  Replacing numerator with 3abc,  3abc / abc = 3 ............hope it will help you....dear

Answer 2

Hey mate here is your answer

a2/bc + b2/ca + c2/ab  LCMof the denominators bc, ca and ab is abc.  =(a3 + b3 + c3) / abc  Given that a + b + c = 0  Thus, a3 + b3 + c3 = 3abc  Replacing numerator with 3abc,  3abc / abc = 3


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