Question

a+b+c=0than the value a²/(a²-bc)+b²/(b²-ca)+c²/(c²-ab)=?

Answer 1

Answer:

I am sorry mere ko nhi pata

Answer 2

Answer:

2

Step-by-step explanation:

From a+b+c=0, a+b=-c

Substituting for -c,

a2/[a2+ b*(a+b)]+ b2/[b2 +a*(a+b)]+ (a+b)2/[(a+b)2-ab]

= a2/(a2+ab+b2) + b2/(a2+ab+b2) + a2+2ab+b2/(a2+ab+b2)

=2(a^2+b^2+ab)/(a^2+b^2+c^2)

=2