Question

a/(b+c)=1/3, (a+c)/b=7/5 then find a,b,c

Answer 1

a/(b+c) =3

a=(b+c)/3............1

b= 5(a+c)/7..............2


Putting value of a in equation 2

a={( 5a+5c)/7 +c}/3

a=( 5a+12c)21

21a=5a+12c

16a=12c

a/c= 3/4 let a= 3k b=4k

3k= (b+4k)/3

9k=b+4k
b=5k


any value of k satisfy these equations

So answer is

a= 3
b=4
c=5



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