A+b+c=1 àb+bc+ca=2 ,abc=3 then 1/a+bc+1/b+ca+1/c+ab =?
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given,
a+b+c=1
ab+bc+ca=2
abc=3
to find :1/a+bc+1/b+ca+1/c+ab
solution :1/a+bc+1/b+ca+1/c+ab
=1/a+1/b+1/c+(bc+ca+ab)
=1/a+1/b+1/c+2[given]
=(bc+ac+ab)/abc+2 [takingLCM]
=2/3+2[given]
=2+6/3[taking LCM]
=8/3
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