(a + b, c + 1) is a solution of the equation y = 2x, If a = 2k, b = 5k, c = 7k; k ≠ 0 and k ∈ R, then find the value of k.
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y=2x
c+1=2(a+b)
7k+1=2(2k+5k)
7k+1=14k
7k=1
k=1/7
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Solution :
It is given that ,
a = 2k , b = 5k , c = 7k , k ≠ 0 , k€ R
( a + b , c + 1 )
= ( 2k + 5k , 7k + 1 )
= ( 7k , 7k + 1 )
Now ,
( a + b , c + 1 ) = ( 7k , 7k + 1 ) is a
solution of y = 2x
=> 7k+ 1 = 2( 7k )
=> 7k + 1 = 14k
=> 1 = 14k - 7k
=> 1 = 7k
=> 7k = 1
=> k = 1/7
•••••
It is given that ,
a = 2k , b = 5k , c = 7k , k ≠ 0 , k€ R
( a + b , c + 1 )
= ( 2k + 5k , 7k + 1 )
= ( 7k , 7k + 1 )
Now ,
( a + b , c + 1 ) = ( 7k , 7k + 1 ) is a
solution of y = 2x
=> 7k+ 1 = 2( 7k )
=> 7k + 1 = 14k
=> 1 = 14k - 7k
=> 1 = 7k
=> 7k = 1
=> k = 1/7
•••••
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