Math, asked by snehaminnu910, 5 hours ago

A+B+C=1 prove that cotAcotC+cotC. CotA+cotA. CotB=2

Answers

Answered by nishii1009
1

Answer:

In ΔABC , A+B+C=180

⟹A+B=180

−C

⟹cot(A+B)=cot(180

−C)

cotA+cotB

cotA.cotB−1

=−cotC

⟹cotA.cotB−1=−cotA.cotC−cotB.cotC

⟹cotA.cotB+cotB.cotC+cotC.cotA=1

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