যদি (a+b+C) = 10 এবং a2 +b2 +C2 = 38 হয় তবে (ab+ bC + ca )এর মান কত ?
Answers
Answered by
0
Answer:
(a+b*c)^2=100
a^2+b^2+c^2+2ab+2bc+2ac=100
2(ab+bc+ac)=100-38=62
ab+bc+ac=62/2=31
Similar questions