a+b+c=10, a2+b2+c2=40 then ab+bc+ca=?
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We know that ,
=(a+b+c)^2=a2+b2+c2 + ab+bc+ca
=(a+b+c)^2=a2+b2+c2 + ab+bc+ca =(10)^2=40+ab+bc+ca
=(a+b+c)^2=a2+b2+c2 + ab+bc+ca =(10)^2=40+ab+bc+ca =100=40+ab+bc+ca
=(a+b+c)^2=a2+b2+c2 + ab+bc+ca =(10)^2=40+ab+bc+ca =100=40+ab+bc+ca= 100-40 =ab+bc+ca
=(a+b+c)^2=a2+b2+c2 + ab+bc+ca =(10)^2=40+ab+bc+ca =100=40+ab+bc+ca= 100-40 =ab+bc+ca=60=ab+bc+ca
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