Question

a+b+c=-10,a²+b²+c²=8 find ab+bc+ca​

Answer 1

Answer:

46

Step-by-step explanation:

given that ;

a+b+c = -10 ; a^2 + b^2 + c^2 =8 ;

we know that ; (a+b+ c)^2 = a^2+ b^2+c^2

+2(ab+bc+ac)

=( -10)^2= 8+ 2(ab +bc + ac)

= 100 -8 = 2( ab+bc+ac)

ab + bc + ac = 92/2

ab + bc + ac = 46