a+b+c=10 and ab+bc+ca=8, find a²+b²+c².
Answers
Answered by
6
Answer:
84
Step-by-step explanation:
⇒ a + b + c = 10
Square on both sides:
⇒ (a + b + c)² = 10²
⇒ a² + b² + c² + 2(ab + bc + ca) = 100
⇒ a² + b² + c² + 2(8) = 100
⇒ a² + b² + c² = 100 - 16
⇒ a² + b² + c² = 84
Answered by
0
Answer:
a+b+c = 10
(a+b+c)^2=100
a^2+b^2+c^+2ab+2bc+2ac=100
a^2+b^2+c^2+2(ab+bc+ac)=100
a^2+b^2+c^2+2(8)=100
a^2+b^2+c^2+16=100
a^2+b^2+c^2= 84
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