Question

(a+b):c=11:4, (b+c):a=26:9, find (c+a):b​

Answer 1

Explanation :-

Solution: (a+b):c=11:4 , or

4a+4b = 11c, or

36a+36b = 99c, or

36b = 99c-36a …(1)

(b+c):a =26:9, or

9b+9c = 26a, or

36b+36c = 104a, or

36b = 104a - 36c …(2)

Equate (1) and (2): 99c-36a = 104a - 36c, or

104a + 36a = 99c + 36c, or

140a = 135c, or

28a = 27c.

Again, 4a+4b = 11c, or

4b = 11c-4a = 11*(28a/27)-4a = (308a-108a)/27 = 200a/27

200a = 108b, or

50a = 27b

a = (27/50)b or b = 50a/27

c+a = (28a/27)+a = 55a/27

(c+a):b = 55a/27 : 50a/27 = 11:10. Answer.

Please mark me as brainlist !!!