a+b+c=12 a2+b2+c2=150 then find 3( ab+ bc+ ca )
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1
Answer:
-9
Step-by-step explanation:
a+b+c = 12
a²+b²+c² = 150
Now ,
(a+b+c)² = a²+b²+c²+2(ab+bc+ca)
12² = 150 + 2(ab+bc+ca)
144 = 150 + 2(ab+bc+ca)
-6 = 2(ab+bc+ca)
-3 = ab+bc+ca
Then, according to the question-
3(ab+bc+ca) = 3 * (-3)
= -9
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