a(b+c_=120,
b(c+a)=144,
c(a+b)=168
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what is your question i can not understand
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Answer:
a=6,b=18,c=2
Step-by-step explanation:
ab+ac=120—(I)
bc+ab=144—(ii)
ca+cb=168—(iii)
from (iii)-(I) we get
ca-ab=24—(iv)
from (I)+(iv) we get
ca=12—(v)
sub [ca=12] in (iii)
cb=156—(vi)
sub [(v)] in (I) we get
ab=108—(vii)
from [(v),(vi),and(vii)] in [(I),(ii) and (iii)]
we get
- 6(18+2)=120
- 18(2+6)=144
- 2(6+18)=168
therefore,a=6,b=18,c=2
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