Math, asked by saumhra9007, 1 month ago

a(b+c_=120,
b(c+a)=144,
c(a+b)=168

Answers

Answered by sarkarrumki971
0

what is your question i can not understand

Answered by pavithra4978
0

Answer:

a=6,b=18,c=2

Step-by-step explanation:

ab+ac=120—(I)

bc+ab=144—(ii)

ca+cb=168—(iii)

from (iii)-(I) we get

ca-ab=24—(iv)

from (I)+(iv) we get

ca=12—(v)

sub [ca=12] in (iii)

cb=156—(vi)

sub [(v)] in (I) we get

ab=108—(vii)

from [(v),(vi),and(vii)] in [(I),(ii) and (iii)]

we get

  • 6(18+2)=120
  • 18(2+6)=144
  • 2(6+18)=168

therefore,a=6,b=18,c=2

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