Math, asked by ravi6515, 11 months ago

a+b+c=12anda2+b2+c2=64,find the ab+bc+ac​

Answers

Answered by duragpalsingh
1

Hey there!

Answer:

(ab + bc + ca) = 40

Step-by-step explanation:

Given,

a² + b² + c² = 64

( a + b + c) = 12

Sqauring both sides:

(a + b + c)² = (12)²

a² + b² + c² + 2 ( ab + bc + ca) = 144

64 + 2 (ab + bc + ca) = 144

2 ( ab + bc + ca) = 144 - 64

2 ( ab + bc + ca) = 80

( ab + bc + ca) = 80 / 2

(ab + bc + ca) = 40

Hope It helps You!

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