a+b+c=12anda2+b2+c2=64,find the ab+bc+ac
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Hey there!
Answer:
(ab + bc + ca) = 40
Step-by-step explanation:
Given,
a² + b² + c² = 64
( a + b + c) = 12
Sqauring both sides:
(a + b + c)² = (12)²
a² + b² + c² + 2 ( ab + bc + ca) = 144
64 + 2 (ab + bc + ca) = 144
2 ( ab + bc + ca) = 144 - 64
2 ( ab + bc + ca) = 80
( ab + bc + ca) = 80 / 2
(ab + bc + ca) = 40
Hope It helps You!
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