A+b+c=13 what is the minimum value of (a-3)(b-2)(c+1)
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Answer:
A+B+C=13 ,
SO , A=13-B-C
SAME WILL OCCUR AT VALUES OF B AND C
B=13-A-C
C=13-A-B
SO PUT THE VALUES IN THE EQ -2
(13-B-C-3) * (13-A-C-2)*(13-A-B+1)
SOLVE THIS .. YOU WILL GET THE ANSWER AND PUT THE VALUE OF A,B,C IN THEIR EQ.
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