Question

a+b+c=15, a²+b²+c²=83 and a³ +b³+ c³=495 then find the value of
abc. Also ab+bc+ca​

Answer 1

Answer:

71

Step-by-step explanation:

i hope this answer helped you

Answer 2

Answer:

a³+b³+c³ = (a + b + c)(a²+b²+c²-ab-bc-ca)

495= (15)(83)-ab-bc-ca

495 = 1245-(ab+bc+ca)

495-1245 = -(ab+bc+ca)

-750 = -(ab+bc+ca)

Minus sign will cut from both side

750=ab+bc+ca