Question

a+b+c =15 ab+bc+ca=25 find the value of a^2+b^2+c^2=?​

Answer 1

Answer:

Answer:

(a+b+c)^2 = a^2 + b^2 + c^2 + 2(ab + bc + ca)

152 = a^2 + b^2 + c^2 + 2(25)

225 = a^2 + b^2 + c^2 + 50

a^2 + b^2 + c^2 = 225 - 50

a^2 + b^2 + c^2 = 175

Answer 2

Answer:

175

Step-by-step explanation:

Solution:--

$given \: \: a + b + c = 15 \\ ab + bc + ca = 25 \\ we \: know \: that \: { ( a + b + c)}^{2} = {a }^{2} + {b}^{2} + {c}^{2} + 2(ab + bc + ca) \\ = > ( {15})^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2(25) \\ = > 225 = {a}^{2} + {b}^{2} + {c}^{2} + 50 \\ = > {a}^{2} + {b}^{2} + {c}^{2} + = 225 - 50 \\ {a}^{2} + {b}^{2} + {c}^{2} = 175 \: \: \: \: ans.$