Question

a+b+c =18 and a² + b²+c²=70
then value of ab+bc+ca is :





​

Answer 1

it may help you marke me

Answer 2

Answer:

here is ur answer....

Answer = 127

Step-by-step explanation:

if a+b+c = 18 & a^2+b^2+c^2 = 70

using identity...

(a+b+c)^2= a^2+b^2+c^2+2(ab + bc + ca)

(18)^2= 70+2 (ab + bc +ca )

324 = 70+ 2 (ab + bc + ca )

324- 70 = 2 (ab + bc +ca )

254/2 = ab + bc + ca

127 = ab+bc+ ca..

hope this is helpful.. plzz mark me as the brainliest...