a+b+c=180 and cosa =cosb cosc then prove that cotb cotc=1/2
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Answered by
39
cosa=cosb cosc
sina/cosa=(sina/cosb cosc)
tana=sin(b+c)/cosb cosc
tana=sinb cosc+cosb sinc/cosb cosc
tana=tanb +tanc
then tan(b+c)=tanb+tanc/1-tanb tanc
-tana = tana/1-tanb tanc
tanb tanc= 2
cotb cotc =1/2 from a+b+c= 180
sina/cosa=(sina/cosb cosc)
tana=sin(b+c)/cosb cosc
tana=sinb cosc+cosb sinc/cosb cosc
tana=tanb +tanc
then tan(b+c)=tanb+tanc/1-tanb tanc
-tana = tana/1-tanb tanc
tanb tanc= 2
cotb cotc =1/2 from a+b+c= 180
Answered by
11
Answer:
Step-by-step explanation:
cosa=cosb cosc
sina/cosa=(sina/cosb cosc)
tana=sin(b+c)/cosb cosc
tana=sinb cosc+cosb sinc/cosb cosc
tana=tanb +tanc
then tan(b+c)=tanb+tanc/1-tanb tanc
-tana = tana/1-tanb tanc
tanb tanc= 2
cotb cotc =1/2 from a+b+c= 180
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