Question

A+B+C=180. sin2A-sin2B+sin2C

Answer 1

Answer:

Step-by-step explanation:

Hey mate here is your answer

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Sin2A+sin2B+sin2C,

2×sin(2A+2B)/2×cos(2A-2B)/2+sin2C,

=>2sin(180°-(A+B)×cos(A-B)+2sinC×cosC,

=>2sinC×cos(A-B)+2sinC×cosC,

=>2sinC[cos(A-B)+cosC],

=>2sinC[cos(A-B)×cos(180°-(A+B)],

=>2sinC[2sin(A-B+A+B)/2×sin(A+B-A+B)],

=>2sinC[2sinA×sinB],

⇒4sinA×sinB×sinC is the correct answer.✔✔✔✔✔

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Hope it helps you mate and please do mark me as Brainliest.