Question

A+B+C=180 then sin^2A-sin^2B-sin^2C=?

Answer 1

Answer:

plz mark as Brainlist hope this will help

Step-by-step explanation:

A+B+C=180

LHS=sin2A+sin2B+sin2C

=2sin(A+B)cos(A−B)+2sinCcosC

=2sinCcos(A−B)+2sinCcosC

=2sinC(cos(A−B)+cosC)

=2sinC(cos(A−B)−cos(A+B))

=2sinC2sinAsinB

=4sinAsinBsinC

= rhs