Question

(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca​

Answer 1

Answer:

i) For a=2,b=4,c=6 we have

(a+b+c)

2

=(12)

2

=144 and

a

2

+b

2

+c

2

+2ab+2bc+2ca

=4+16+36+16+48+24

=144

ii) For a=5,b=−2,c=3 we have

(a+b+c)

2

=(6)

2

=36 and

a

2

+b

2

+c

2

+2ab+2bc+2ca

=25+4+9−20−12+30

=36

iii) For a=−2,b=3,c=−4 we have

(a+b+c)

2

=(−3)

2

=9 and

a

2

+b

2

+c

2

+2ab+2bc+2ca

=4+9+16−12−24+16

=9